$B {(OH)}_{3} + NaOH ⇌ Na [B (OH)_{4}]$ How this reaction can is made to proceed in forward direction?

Question

B {(OH)}_{3} + NaOH ⇌ Na [B (OH)_{4}]

How this reaction can is made to proceed in forward direction? (A) Addition of cis 1,2 diol (B) Addition of borax (C) Addition of trans 1,2 diol (D) Addition od

N a_{2} H P O_{4}

Tardigrade Admin · Accepted Answer

$[B (O H)_{4}]^{-}$ forms compound with cis 1,2 diol i.e. it consumes the product so according to le chatelier principle the reaction goes in forward direction. The complex anion formed with cis 1,2 diol is stable due to formation of 5 membered ring.

Q. B (OH) 3 +NaOH ⇌ Na[B OH ) 4 How this reaction can is made to proceed in forward direction?

Addition of cis 1,2 diol

Addition of borax

Addition of trans 1,2 diol

Addition od Na2HPO4

[B(OH)4]- forms compound with cis 1,2 diol i.e. it consumes the product so according to le chatelier principle the reaction goes in forward direction. The complex anion formed with cis 1,2 diol is stable due to formation of 5 membered ring.

Q. $B {(OH)}_{3} + NaOH ⇌ Na [B (OH)_{4}]$
How this reaction can is made to proceed in forward direction?

Addition od $N a_{2} H P O_{4}$

$[B (O H)_{4}]^{-}$ forms compound with cis 1,2 diol i.e. it consumes the product so according to le chatelier principle the reaction goes in forward direction. The complex anion formed with cis 1,2 diol is stable due to formation of 5 membered ring.