ATP + H 2 O arrow ADP + PO 43- ; Δr G°=-31 kJ / mol Glucose + Fructose arrow Sucrose; Δr G°=23 kJ / mol A 100 ml solution is 0.5( M ) with respect to glucose and 0.8( M ) with respect to fructose. To this how many liters of gastric juice containing 10-2(M) ATP is to be added to obtain maximum molarity of sucrose?

Question

ATP + H 2 O arrow ADP + PO 43- ; Δr G°=-31 kJ / mol Glucose + Fructose arrow Sucrose; Δr G°=23 kJ / mol A 100 ml solution is 0.5( M ) with respect to glucose and 0.8( M ) with respect to fructose. To this how many liters of gastric juice containing 10-2(M) ATP is to be added to obtain maximum molarity of sucrose? (A) 3 L (B) 2.71 L (C) 37.1 L (D) 3.71 L

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/e65ca48927a390dae83889ac2c53f27a-.png" /> Glucose is the L.R. and maximum amount of sucrose to be obtained =5 × 10-2 mol ∴ Energy required =23 × 5 × 10-2 kJ Let V ml of ATP solution is required V × 10-5 × 31=23 × 5 × 10-2 ∴ V=(23 × 5/31) × 103=3.71 × 103 mL =3.71 L

$3 L$

$2.71 L$

$37.1 L$

$3.71 L$

3L

2.71L

37.1L

3.71L

Glucose is the L.R. and maximum amount of sucrose to be obtained =5×10−2mol ∴ Energy required =23×5×10−2kJ Let Vml of ATP solution is required V×10−5×31=23×5×10−2 ∴V=3123×5​×103=3.71×103mL=3.71L

$3 L$

$2.71 L$

$37.1 L$

$3.71 L$