Atomic numbers of vanadium, chromium, nickel and iron are 23, 24, 28 and 26 respectively. Which one of these is expected to have the highest second ionization enthalpy?

Question

Atomic numbers of vanadium, chromium, nickel and iron are 23, 24, 28 and 26 respectively. Which one of these is expected to have the highest second ionization enthalpy? (A) Cr (B) V (C) Fe (D) Ni

Tardigrade Admin · Accepted Answer

Second ionization enthalpy of Cr is highest. because after the removal of 1st electron, Cr acquires -a. stable half-filled d5 configuration thus, removal of 2nd electron is very difficult.

Q. Atomic numbers of vanadium, chromium, nickel and iron are $23, 24, 28$ and $26$ respectively. Which one of these is expected to have the highest second ionization enthalpy?

$C r$

$V$

$F e$

$N i$

Second ionization enthalpy of Cr is highest. because after the removal of $1^{s t}$ electron, Cr acquires -a. stable half-filled $d^{5}$ configuration thus, removal of $2^{n d}$ electron is very difficult.

Q. Atomic numbers of vanadium, chromium, nickel and iron are 23,24,28 and 26 respectively. Which one of these is expected to have the highest second ionization enthalpy?

Cr

V

Fe

Ni