Question

At what angle should the two forces $2P$ and $\sqrt{2}P$ act so that the resultant force is ? $P\sqrt{10}$

• A. $45^{\circ }$
• B. $60^{\circ }$
• C. $90^{\circ }$
• D. $120^{\circ }$

Answer 1

Answer: (A)

Resultant, $R=\sqrt{A^2+B^2+2AB\cos \theta }$
$P\sqrt{10}=\sqrt{4P^2+2P^2+4\sqrt{2}{P}^2\cos \theta }$
$\therefore \theta =45^{\circ }$