At time t = 0 second, voltage of an A.C. Generator starts from 0V and becomes 2V at time t=(1/100 π ) second. The voltage keeps on increasing up 100V, after which it starts to decrease. Find the frequency of the Generator.

Question

At time t = 0 second, voltage of an A.C. Generator starts from 0V and becomes 2V at time t=(1/100 π ) second. The voltage keeps on increasing up 100V, after which it starts to decrease. Find the frequency of the Generator. (A) 100 Hz (B) 1 Hz (C) 2 Hz (D) 5 Hz

Tardigrade Admin · Accepted Answer

ϵ = ϵ 0sin w t ϵ 0=maximum voltage=100V. at t=(1/100 π ); ϵ =100sin w((1/100 π ))=2V sin (w/100 π ) = (2/100) (w/100 π )=0.02 (for small θ , sinθ âθ ) w=2π f=(w/2 π )=1 Hz

Q. At time t = 0 second, voltage of an A.C. Generator starts from 0V and becomes 2V at time $t = \frac{1}{100 π}$ second. The voltage keeps on increasing up 100V, after which it starts to decrease. Find the frequency of the Generator.

$100 Hz$

$1 Hz$

$2 Hz$

$5 Hz$

$ϵ = ϵ_{0} s in wt$
$ϵ_{0} = ma x im u m v o lt a g e = 100 V .$
at $t = \frac{1}{100 π}; ϵ = 100 s in w (\frac{1}{100 π}) = 2 V$
$s in \frac{w}{100 π} = \frac{2}{100}$
$\frac{w}{100 π} = 0.02 (f or s ma ll θ, s in θ \approx θ)$
$w = 2 π$
$f = \frac{w}{2 π} = 1 Hz$

Q. At time t = 0 second, voltage of an A.C. Generator starts from 0V and becomes 2V at time t=100π1​ second. The voltage keeps on increasing up 100V, after which it starts to decrease. Find the frequency of the Generator.

100Hz

1Hz

2Hz

5Hz