At time t = 0 magnetic field of 1000 Gauss is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to 500 Gauss, in the next 5 s, then induced EMF in the loop is :

Question

At time t = 0 magnetic field of 1000 Gauss is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to 500 Gauss, in the next 5 s, then induced EMF in the loop is : (A) 36 μ V (B) 48 μ V (C) 56 μ V (D) 28 μ V

Tardigrade Admin · Accepted Answer

(dB/dt)=100 A=16 Ã4 - 4 Ã 2 = 56 cm2 ε=(dB/dt)A=100×10-4×56×10-4

Q. At time t = 0 magnetic field of 1000 Gauss is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to 500 Gauss, in the next 5 s, then induced EMF in the loop is :

$36 μ V$

$48 μ V$

$56 μ V$

$28 μ V$

$\frac{d B}{d t} = 100$
$A = 16 \times 4 - 4 \times 2 = 56 c m^{2}$
$ε = \frac{d B}{d t} A = 100 \times 1 0^{- 4} \times 56 \times 1 0^{- 4}$

Q. At time t = 0 magnetic field of 1000 Gauss is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to 500 Gauss, in the next 5 s, then induced EMF in the loop is :

36μV

48μV

56μV

28μV

dtdB​=100 A=16×4−4×2=56cm2 ε=dtdB​A=100×10−4×56×10−4

$36 μ V$

$48 μ V$

$56 μ V$

$28 μ V$

$\frac{d B}{d t} = 100$
$A = 16 \times 4 - 4 \times 2 = 56 c m^{2}$
$ε = \frac{d B}{d t} A = 100 \times 1 0^{- 4} \times 56 \times 1 0^{- 4}$