At the same temperature which of the following solutions will be isotonic?

Question

At the same temperature which of the following solutions will be isotonic? (A) 3.42 g of sucrose per litre of water and 0.18 g of glucose per litre of water. (B) 3.42 g of sucrose per litre of water and 0.18 g of glucose in 0.1 litre of water. (C) 3.42 g of sucrose per litre of water and 0.585 g of sodium chloride per litre of water. (D) 3.42 g of sucrose per litre of water and 1.17 g of sodium chloride per litre of water.

Tardigrade Admin · Accepted Answer

For isotonic solution, Ï1 = Ï2 or C1 = C2 For 3.42 g sucrose in 1 L of water and 0.18 g glucose in 0.1 L of water. (3.42/342×1) = (0.18/180×0.1) or 0.01 = 0.01 ∴ They are isotonic.

Q. At the same temperature which of the following solutions will be isotonic?

3.42 g of sucrose per litre of water and 0.18 g of glucose per litre of water.

3.42 g of sucrose per litre of water and 0.18 g of glucose in 0.1 litre of water.

3.42 g of sucrose per litre of water and 0.585 g of sodium chloride per litre of water.

3.42 g of sucrose per litre of water and 1.17 g of sodium chloride per litre of water.

For isotonic solution, $π_{1} = π_{2}$ or $C_{1} = C_{2}$
For 3.42 g sucrose in 1 L of water and 0.18 g glucose in 0.1 L of water.
$\frac{3.42}{342 \times 1} = \frac{0.18}{180 \times 0.1}$ or $0.01 = 0.01$
$∴$ They are isotonic.

Q. At the same temperature which of the following solutions will be isotonic?

3.42 g of sucrose per litre of water and 0.18 g of glucose per litre of water.

3.42 g of sucrose per litre of water and 0.18 g of glucose in 0.1 litre of water.

3.42 g of sucrose per litre of water and 0.585 g of sodium chloride per litre of water.

3.42 g of sucrose per litre of water and 1.17 g of sodium chloride per litre of water.

For isotonic solution, π1​=π2​ or C1​=C2​ For 3.42 g sucrose in 1 L of water and 0.18 g glucose in 0.1 L of water. 342×13.42​=180×0.10.18​ or 0.01=0.01 ∴ They are isotonic.

For isotonic solution, $π_{1} = π_{2}$ or $C_{1} = C_{2}$
For 3.42 g sucrose in 1 L of water and 0.18 g glucose in 0.1 L of water.
$\frac{3.42}{342 \times 1} = \frac{0.18}{180 \times 0.1}$ or $0.01 = 0.01$
$∴$ They are isotonic.