At the point of intersection of the two curves shown, the conc. of B is given by for, A longrightarrow n B :

Question

At the point of intersection of the two curves shown, the conc. of B is given by for, A longrightarrow n B : (A) (n A0/2) (B) (A0/n-1) (C) (n A0/n+1) (D) ((n-1/n+1)) A0

Tardigrade Admin · Accepted Answer

From the fig. [ A ] text left =[ B ] text formed =n ×[ A ] text decayed ∴ [A0]e-λ t=n × A0[1-e-λ t] ∴ e-λ t=(n/n+1) [ B ] text formed =n × A0 ×[1-(n/n+1)]=(n A0/n+1)

Q. At the point of intersection of the two curves shown, the conc. of $B$ is given by ____ for, $A ⟶ n B$ :

$\frac{n A _{0}}{2}$

$\frac{A _{0}}{n - 1}$

$\frac{n A _{0}}{n + 1}$

$(\frac{n - 1}{n + 1}) A_{0}$

From the fig. $[A]_{left} = [B]_{formed} = n \times [A]_{decayed}$
$∴ [A_{0}]_{e}^{- λ t} = n \times A_{0} [1 - e^{- λ t}]$
$∴ e^{- λ t} = \frac{n}{n + 1}$
$[B]_{formed} = n \times A_{0} \times [1 - \frac{n}{n + 1}] = \frac{n A _{0}}{n + 1}$

Q. At the point of intersection of the two curves shown, the conc. of B is given by ____ for, A⟶nB :

2nA0​​

n−1A0​​

n+1nA0​​

(n+1n−1​)A0​