At T(K) if the rate constant for a zero order reaction is 2.5 × 10-3 ms-1 . the time required for the initial concentration of reactant. R to fall from 0.10 M to 0.075 M at the same temperature in seconds is

Question

At T(K) if the rate constant for a zero order reaction is 2.5 × 10-3 ms-1 . the time required for the initial concentration of reactant. R to fall from 0.10 M to 0.075 M at the same temperature in seconds is (A) 25 (B) 5 (C) 10 (D) 20

Tardigrade Admin · Accepted Answer

t =([R0]-[R]E/K) t=(0.1-0.075/2.5 × 10-3) =(0.025/2.5 × 10-3) t=0.01 × 103=10 s

Q. At $T (K)$ if the rate constant for a zero order reaction is $2.5 \times 1 0^{- 3} m s^{- 1}$ . the time required for the initial concentration of reactant. R to fall from $0.10 M$ to $0.075 M$ at the same temperature in seconds is

25

5

10

20

$t = \frac{[ R _{0} ] - [ R ] _{E}}{K} t = \frac{0.1 - 0.075}{2.5 \times 1 0 ^{- 3}}$

$= \frac{0.025}{2.5 \times 1 0 ^{- 3}} t = 0.01 \times 1 0^{3} = 10 s$

Q. At T(K) if the rate constant for a zero order reaction is 2.5×10−3ms−1 . the time required for the initial concentration of reactant. R to fall from 0.10M to 0.075M at the same temperature in seconds is

25

5

10

20

t=K[R0​]−[R]E​​t=2.5×10−30.1−0.075​ =2.5×10−30.025​t=0.01×103=10s

Q. At $T (K)$ if the rate constant for a zero order reaction is $2.5 \times 1 0^{- 3} m s^{- 1}$ . the time required for the initial concentration of reactant. R to fall from $0.10 M$ to $0.075 M$ at the same temperature in seconds is

$t = \frac{[ R _{0} ] - [ R ] _{E}}{K} t = \frac{0.1 - 0.075}{2.5 \times 1 0 ^{- 3}}$

$= \frac{0.025}{2.5 \times 1 0 ^{- 3}} t = 0.01 \times 1 0^{3} = 10 s$