At t=0, a stone of mass 10 g is thrown straight up from the ground level with a speed 10 m / s. After 1 s a second stone of the same mass is thrown from the same position with a speed 20 m / s. What is the position of the 1st stone from the ground level at that moment? (take g =10 m / s 2 )

Question

At t=0, a stone of mass 10 g is thrown straight up from the ground level with a speed 10 m / s. After 1 s a second stone of the same mass is thrown from the same position with a speed 20 m / s. What is the position of the 1st stone from the ground level at that moment? (take g =10 m / s 2 ) (A) 10 m (B) 1 m (C) 2m (D) 5 m

Tardigrade Admin · Accepted Answer

Distance covered in 1 s h=u t-(1/2) g t2 =10 × 1-(1/2) × 10 × 12 =10-5=5 cm So, the position of 1 textst stone from the ground is 5 m.

Q. At t=0, a stone of mass 10g is thrown straight up from the ground level with a speed 10m/s. After 1s a second stone of the same mass is thrown from the same position with a speed 20m/s. What is the position of the 1st stone from the ground level at that moment? (take g=10m/s2 )

10 m

1 m

2m

5 m

Distance covered in 1s h=ut−21​gt2 =10×1−21​×10×12 =10−5=5cm So, the position of 1st stone from the ground is 5m.

Distance covered in $1 s$
$h = u t - \frac{1}{2} g t^{2}$
$= 10 \times 1 - \frac{1}{2} \times 10 \times 1^{2}$
$= 10 - 5 = 5 c m$
So, the position of $1^{st}$ stone from the ground is $5 m$ .