At constant temperature, the equilibrium constant (Kp) the decomposition reaction, N 2 O 4 leftharpoons NO 2, is expressed by Kp=(4 x2 p/(1-x2)), where, p= pressure, x= extent of decomposition. Which one of the following statement is true?

Question

At constant temperature, the equilibrium constant (Kp) the decomposition reaction, N 2 O 4 leftharpoons NO 2, is expressed by Kp=(4 x2 p/(1-x2)), where, p= pressure, x= extent of decomposition. Which one of the following statement is true? (A) Kp increases with increase of p (B) Kp increases with increase of x (C) Kp increases with decrease of x (D) K p remains constant with change in p and x

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/10b4f829d45968218a118334a3a8df11-.png" /> Kp is function of temperature only, does not change with either p or x.

Q. At constant temperature, the equilibrium constant $(K_{p})$ the decomposition reaction, $N_{2} O_{4} ⇌ N O_{2}$ , is expressed by $K_{p} = \frac{4 x ^{2} p}{( 1 - x ^{2} )}$ , where, $p =$ pressure, $x =$ extent of decomposition. Which one of the following statement is true?

$K_{p}$ increases with increase of $p$

$K_{p}$ increases with increase of $x$

$K_{p}$ increases with decrease of $x$

$K_{p}$ remains constant with change in $p$ and $x$

$K_{p}$ is function of temperature only, does not change with either $p$ or $x .$

Q. At constant temperature, the equilibrium constant (Kp​) the decomposition reaction, N2​O4​⇌NO2​, is expressed by Kp​=(1−x2)4x2p​, where, p= pressure, x= extent of decomposition. Which one of the following statement is true?

Kp​ increases with increase of p

Kp​ increases with increase of x

Kp​ increases with decrease of x

Kp​ remains constant with change in p and x