Question

At constant P of 0.0821 atm log V vs log T graph is plotted for 3 samples of ideal gas as shown. Value of moles of gas in these three samples is respectively:

• A. $3,1,\frac{1}{2}$
• B. $\frac{1}{2},1,3$
• C. $1,\frac{1}{2},3$
• D. $\frac{1}{2},3,1$

Answer 1

Answer: (A)

$\frac{V}{T}=$ constant $(K)$

$\log V=\log T+\log K$ where $K=\frac{nR}{P}$

For 2 graph

$\log \frac{nR}{P}=0=\log 1$

$\frac{nR}{P}=1(R=P)\text{ or }n=1mol$

for 1 graph

$\log \frac{nR}{P}=\log 3\text{ or }n=3mol$

for 3 graph

$\log \frac{nR}{P}=-\log 2=\log \frac{1}{2}$

$n=\frac{1}{2}mol$