Question

At certain temperature and a total pressure of $\text{1}{\text{0}}^{\text{5}}\text{Pa,}$ iodine vapours contains 40% by volume of iodine atoms. $K_p$ for the equilibrium, $I_2(g)2I(g);$ will be

• A. $0.67$
• B. $1.5$
• C. $2.67\times {10}^4$
• D. $9.0\times {10}^4$

Answer 1

Answer: (C)

Partial pressure of iodine atoms
$(p_1)=\frac{40}{100}\times {10}^5$
$=0.40\times {10}^{5}Pa$
Partial pressure of $l_2(p{l}_2)$
$=\frac{60}{100}\times {10}^{5}Pa$
$=0.60\times {10}^{5}Pa$
$\therefore$ $K_p=\frac{p_l^2}{p_{l_2}}=\frac{{(0.40\times {10}^5)}^2}{0.60\times {10}^5}$
$=2.67\times {10}^4$