At a temperature of 273 K and pressure of 2 atm the weight of 305 mL of a diatomic gas is 1 g . What is the weight of one atom? ( N is the Av. no.)

Question

At a temperature of 273 K and pressure of 2 atm the weight of 305 mL of a diatomic gas is 1 g . What is the weight of one atom? ( N is the Av. no.) (A) (16/ textN) (B) (32/ textN) (C) 16 N (D) 32 N

Tardigrade Admin · Accepted Answer

Calculate M =(R T w/P V) Wt . of one atom =M / (N × 2)

Q. At a temperature of $273 K$ and pressure of $2$ atm the weight of $305 m L$ of a diatomic gas is $1 g$ . What is the weight of one atom? ( $N$ is the Av. no.)

$\frac{16}{N}$

$\frac{32}{N}$

$16 N$

$32 N$

Calculate $M = \frac{RTw}{P V}$
$W t$ . of one atom $= M / (N \times 2)$

Q. At a temperature of 273K and pressure of 2 atm the weight of 305mL of a diatomic gas is 1g . What is the weight of one atom? ( N is the Av. no.)

N16​

N32​

16N

32N