At a pressure of 24 × 105 dyne/cm2, the volume of O2 is 10litre and mass is 20 gm. The r.m.s velocity will be

Question

At a pressure of 24 × 105 dyne/cm2, the volume of O2 is 10litre and mass is 20 gm. The r.m.s velocity will be (A) 800 m/sec (B) 400 m/sec (C) 600 m/sec (D) 200 m/sec

Tardigrade Admin · Accepted Answer

V rms =√(3 PV / m )=√(3 × 24 × 104 × 10 × 10-3/20 × 10-3) =600 m / s

Q. At a pressure of $24 \times 1 0^{5} d y n e / c m^{2},$ the volume of $O_{2}$ is 10litre and mass is 20 gm. The r.m.s velocity will be

800 m/sec

400 m/sec

600 m/sec

200 m/sec

$V_{r m s} = \frac{3 P V}{m} = \frac{3 \times 24 \times 1 0 ^{4} \times 10 \times 1 0 ^{- 3}}{20 \times 1 0 ^{- 3}}$
$= 600 m / s$

Q. At a pressure of 24×105dyne/cm2, the volume of O2​ is 10litre and mass is 20 gm. The r.m.s velocity will be