At a pressure of 24 × 105 dyne cm -2, the volume of O 2 is 10 litre and mass is 20 g. The rms velocity will be

Question

At a pressure of 24 × 105 dyne cm -2, the volume of O 2 is 10 litre and mass is 20 g. The rms velocity will be (A) 800 ms -1 (B) 400 ms -1 (C) 600 ms -1 (D) Data is incomplete

Tardigrade Admin · Accepted Answer

C=√(3 P V/M) =√(3 × 24 × 105 × 10 × 1000/20) cms -1 =6 × 104 cms -1=600 ms -1

Q. At a pressure of $24 \times 1 0^{5}$ dyne $c m^{- 2}$ , the volume of $O_{2}$ is 10 litre and mass is $20 g$ . The rms velocity will be

$800 m s^{- 1}$

$400 m s^{- 1}$

$600 m s^{- 1}$

Data is incomplete

$C = \frac{3 P V}{M}$
$= \frac{3 \times 24 \times 1 0 ^{5} \times 10 \times 1000}{20} c m s^{- 1}$
$= 6 \times 1 0^{4} c m s^{- 1} = 600 m s^{- 1}$

Q. At a pressure of 24×105 dyne cm−2, the volume of O2​ is 10 litre and mass is 20g. The rms velocity will be

800ms−1

400ms−1

600ms−1