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  4. At a pressure of 24 × 105 dyne cm -2, the volume of O 2 is 10 litre and mass is 20 g. The rms velocity will be

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Q. At a pressure of $24 \times 10^{5}$ dyne $cm ^{-2}$, the volume of $O _{2}$ is 10 litre and mass is $20\, g$. The rms velocity will be

Kinetic Theory

Solution:

$C=\sqrt{\frac{3 P V}{M}}$
$=\sqrt{\frac{3 \times 24 \times 10^{5} \times 10 \times 1000}{20}} cms ^{-1}$
$=6 \times 10^{4} cms ^{-1}=600\, ms ^{-1}$