At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m 3 s -1. If the turbine generator efficiency is 60 %, the electric power available from the plant is (g=9.8 m s -2)

Question

At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m 3 s -1. If the turbine generator efficiency is 60 %, the electric power available from the plant is (g=9.8 m s -2) (A) 116 MW (B) 136 MW (C) 156 MW (D) 176 MW

Tardigrade Admin · Accepted Answer

Hydroelectric power =(P ⋅ E/t)=(mgh/t)=ρ((V/t)) gh Electric power = Efficiency × hydroelectric power =0.6 ×(103 × 100 × 9.8 × 300) =176 MW

Q. At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is $100 m^{3} s^{- 1}$ . If the turbine generator efficiency is $60%,$ the electric power available from the plant is $(g = 9.8 m s^{- 2})$

116 MW

136 MW

156 MW

176 MW

Hydroelectric power $= \frac{P \cdot E}{t} = \frac{m g h}{t} = ρ (\frac{V}{t}) g h$
Electric power = Efficiency $\times$ hydroelectric power
$= 0.6 \times (1 0^{3} \times 100 \times 9.8 \times 300)$
$= 176 M W$

Q. At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100m3s−1. If the turbine generator efficiency is 60%, the electric power available from the plant is (g=9.8ms−2)