At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behaviour. Their equation of state is given as p = (RT/V - b) at T . Here, b is the van der Waals constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs p ?

Question

At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behaviour. Their equation of state is given as p = (RT/V - b) at T . Here, b is the van der Waals constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs p ? (A) Ne (B) Ar (C) Xe (D) Kr

Tardigrade Admin · Accepted Answer

As b uparrow ⇒ slope uparrow Hence, Xe, will have highest slope

Q. At a given temperature T, gases Ne,Ar,Xe and Kr are found to deviate from ideal gas behaviour. Their equation of state is given as p=V−bRT​ at T . Here, b is the van der Waals constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs p ?

Ne

Ar

Xe

Kr

As b↑⇒ slope ↑ Hence, Xe, will have highest slope

As $b ↑ \Rightarrow$ slope $↑$
Hence, Xe, will have highest slope