At a given place where acceleration due to gravity is g m/s2 , a sphere of lead of density d kg/m3 is gently released in a column of liquid of density ρ kg/m3 . If d ρ , the sphere will

Question

At a given place where acceleration due to gravity is g m/s2 , a sphere of lead of density d kg/m3 is gently released in a column of liquid of density ρ kg/m3 . If d > ρ , the sphere will (A) fall vertically with an acceleration g m/s2  (B) fall vertically with no acceleration (C) fall vertically with an acceleration g((d-ρ/d))  (D) fall vertically with an acceleration g((ρ/d))

Tardigrade Admin · Accepted Answer

Apparent weight = actual weight - upthrust V d g' =V d g-V ρ g g' =((d-ρ/d)) g

Q. At a given place where acceleration due to gravity is $g m / s^{2}$ , a sphere of lead of density $d k g / m^{3}$ is gently released in a column of liquid of density $ρ k g / m^{3}$ . If $d > ρ$ , the sphere will

fall vertically with an acceleration $g m / s 2$

fall vertically with no acceleration

fall vertically with an acceleration $g (\frac{d - ρ}{d})$

fall vertically with an acceleration $g (\frac{ρ}{d})$

Apparent weight $=$ actual weight $-$ upthrust
$V d g^{^{'}} = V d g - V ρ g$
$g^{^{'}} = (\frac{d - ρ}{d}) g$

Q. At a given place where acceleration due to gravity is gm/s2 , a sphere of lead of density dkg/m3 is gently released in a column of liquid of density ρkg/m3 . If d>ρ , the sphere will

fall vertically with an acceleration gm/s2

fall vertically with no acceleration

fall vertically with an acceleration g(dd−ρ​)

fall vertically with an acceleration g(dρ​)

Apparent weight = actual weight − upthrust Vdg′=Vdg−Vρg g′=(dd−ρ​)g

Q. At a given place where acceleration due to gravity is $g m / s^{2}$ , a sphere of lead of density $d k g / m^{3}$ is gently released in a column of liquid of density $ρ k g / m^{3}$ . If $d > ρ$ , the sphere will

fall vertically with an acceleration $g m / s 2$

fall vertically with an acceleration $g (\frac{d - ρ}{d})$

fall vertically with an acceleration $g (\frac{ρ}{d})$

Apparent weight $=$ actual weight $-$ upthrust
$V d g^{^{'}} = V d g - V ρ g$
$g^{^{'}} = (\frac{d - ρ}{d}) g$