At a certain place, vertical component of earth's magnetic field is √3 times the horizontal component of earth's magnetic field. If a magnetic needle is suspended freely in air then it will incline

Question

At a certain place, vertical component of earth's magnetic field is √3 times the horizontal component of earth's magnetic field. If a magnetic needle is suspended freely in air then it will incline (A) 30° below horizontal (B) 60° below horizontal (C) 30° above horizontal (D) 45° above horizontal

Tardigrade Admin · Accepted Answer

BV=√3 BH (BV/BH)=√3= tan θ θ=60°

Q. At a certain place, vertical component of earth's magnetic field is $3$ times the horizontal component of earth's magnetic field. If a magnetic needle is suspended freely in air then it will incline

$3 0^{\circ}$ below horizontal

$6 0^{\circ}$ below horizontal

$3 0^{\circ}$ above horizontal

$4 5^{\circ}$ above horizontal

$B_{V} = 3 B_{H}$
$\frac{B _{V}}{B _{H}} = 3 = tan θ$
$θ = 6 0^{\circ}$

Q. At a certain place, vertical component of earth's magnetic field is 3​ times the horizontal component of earth's magnetic field. If a magnetic needle is suspended freely in air then it will incline

30∘ below horizontal

60∘ below horizontal

30∘ above horizontal

45∘ above horizontal