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Q. At a certain place, vertical component of earth's magnetic field is $\sqrt{3}$ times the horizontal component of earth's magnetic field. If a magnetic needle is suspended freely in air then it will incline

Magnetism and Matter

Solution:

$B_{V}=\sqrt{3} B_{H}$
$\frac{B_{V}}{B_{H}}=\sqrt{3}=\tan \theta$
$\theta=60^{\circ}$