At 60° and 1 atm, N2O4 is 50 % dissociated into NO2 then Kp is

Question

At 60° and 1 atm, N2O4 is 50 % dissociated into NO2 then Kp is (A) 1.33 atm (B) 2 atm (C) 2.67 atm (D) 3 atm

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/e6ef1d3935f27ba79ea2bbdf006b4c21-.png" /> N2O4 is 50 % dissociated, so α=(1/2) Kp=(p2NO2/pN2O4)=((2×(1/2))2/(1-(1)2))=2 atm

Q. At $6 0^{\circ}$ and $1$ atm, $N_{2} O_{4}$ is $50%$ dissociated into $N O_{2}$ then $K_{p}$ is

1.33 atm

2 atm

2.67 atm

3 atm

$N_{2} O_{4}$ is $50%$ dissociated, so $α = \frac{1}{2}$
$K_{p} = \frac{p ^{2} N O _{2}}{p N _{2} O _{4}} = \frac{( 2 \times \frac{1}{2} ) ^{2}}{( 1 - \frac{1}{2} )} = 2$ atm

Q. At 60∘ and 1 atm, N2​O4​ is 50% dissociated into NO2​ then Kp​ is