At 300 K, the value of ((Kc/Kp)) will be lowest for

Question

At 300 K, the value of ((Kc/Kp)) will be lowest for (A) N2(g) + O2 (g) <=> 2NO(g) (B) N2(g) + 3H2 (g) <=> 2NH3(g) (C) PCl5(g) <=> PCl3(g) + Cl2(g) (D) 2HI(g) <=> H2(g) + I2 (g)

Tardigrade Admin · Accepted Answer

Kp=Kc(RT)Δ n ⇒ (Kc/Kp)=(RT)-Δ n 1. N2+O2 leftharpoons 2NO, Δ n=0, (Kc/kp)=1 2. N2+3H2 leftharpoons 2NH3, Δ n =-2, (Kc/Kp)=(RT)2 3. PCl5 leftharpoons PCl3+Cl2, Δ n=1, (Kc/Kp)=(RT)-1 4. 2HI leftharpoons H2+I2, Δ n=0, (Kc/Kp)=1

Q. At $300 K$ , the value of $(\frac{K _{c}}{K _{p}})$ will be lowest for

$N_{2} (g) + O_{2} (g) 2 NO (g)$

$N_{2} (g) + 3 H_{2} (g) 2 N H_{3} (g)$

$PC l_{5} (g) PC l_{3} (g) + C l_{2} (g)$

$2 H I (g) H_{2} (g) + I_{2} (g)$

Q. At 300K, the value of (Kp​Kc​​) will be lowest for

N2​(g)+O2​(g)​2NO(g)

N2​(g)+3H2​(g)​2NH3​(g)

PCl5​(g)​PCl3​(g)+Cl2​(g)

2HI(g)​H2​(g)+I2​(g)

Kp​=Kc​(RT)Δn⇒Kp​Kc​​=(RT)−Δn 1. N2​+O2​⇌2NO,Δn=0,kp​Kc​​=1 2. N2​+3H2​⇌2NH3​,Δn=−2,Kp​Kc​​=(RT)2 3. PCl5​⇌PCl3​+Cl2​,Δn=1,Kp​Kc​​=(RT)−1 4. 2HI⇌H2​+I2​,Δn=0,Kp​Kc​​=1

Q. At $300 K$ , the value of $(\frac{K _{c}}{K _{p}})$ will be lowest for

$N_{2} (g) + O_{2} (g) 2 NO (g)$

$N_{2} (g) + 3 H_{2} (g) 2 N H_{3} (g)$

$PC l_{5} (g) PC l_{3} (g) + C l_{2} (g)$

$2 H I (g) H_{2} (g) + I_{2} (g)$