At 298 K a 0.1 M CH 3 COOH solution is 1.34 % ionized. The ionization constant Ka for acetic acid will be

Question

At 298 K a 0.1 M CH 3 COOH solution is 1.34 % ionized. The ionization constant Ka for acetic acid will be (A) 1.82 × 10-5 (B) 18.2 × 10-5 (C) 0.182 × 10-5 (D) None of these

Tardigrade Admin · Accepted Answer

K=c α2=0.1 ×((1.34/100))2=1.8 × 10-5

Q. At $298 K$ a $0.1 M C H_{3} COO H$ solution is $1.34%$ ionized. The ionization constant $K_{a}$ for acetic acid will be

$1.82 \times 1 0^{- 5}$

$18.2 \times 1 0^{- 5}$

$0.182 \times 1 0^{- 5}$

None of these

$K = c α^{2} = 0.1 \times (\frac{1.34}{100})^{2} = 1.8 \times 1 0^{- 5}$

Q. At 298K a 0.1MCH3​COOH solution is 1.34% ionized. The ionization constant Ka​ for acetic acid will be

1.82×10−5

18.2×10−5

0.182×10−5