At 20°C the solubility of N2 gas in water is 0.015 g/L when the partial pressure of N2 is 580 torr. What is the solubility of N2 in H2O at 20°C when its partial pressure is 800 torr?

Question

At 20°C the solubility of N2 gas in water is 0.015 g/L when the partial pressure of N2 is 580 torr. What is the solubility of N2 in H2O at 20°C when its partial pressure is 800 torr? (A) 0.207 g/L (B) 0.0207 g/L (C) 0.414 g/L (D) 0.0414 g/L

Tardigrade Admin · Accepted Answer

At 20° solubility of N2 in water is 0.015 g/L. When partial pressure is 580 torr. According to Henryâs law m propto p m = KH p 0.015 = KH × 580 KH = (580/0.015) For the solubility of N2 in at 20°C = (800/KH) = (800/580) × 0.015 = 0.0207 g/L

Q. At 20∘C the solubility of N2​ gas in water is 0.015g/L when the partial pressure of N2​ is 580 torr. What is the solubility of N2​ in H2​O at 20∘C when its partial pressure is 800 torr?

0.207 g/L

0.0207 g/L

0.414 g/L

0.0414 g/L

At 20∘ solubility of N2​ in water is 0.015g/L. When partial pressure is 580 torr. According to Henry’s law m∝p m=KH​p 0.015=KH​×580 KH​=0.015580​ For the solubility of N2​ in at 20∘C =KH​800​=580800​×0.015 =0.0207g/L

Q. At $2 0^{\circ} C$ the solubility of $N_{2}$ gas in water is $0.015 g / L$ when the partial pressure of $N_{2}$ is $580$ torr. What is the solubility of $N_{2}$ in $H_{2} O$ at $2 0^{\circ} C$ when its partial pressure is $800$ torr?