At 1990 K and 1 atm pressure, there are equal number of Cl 2 molecules and Cl atoms in the reaction mixture. The value K P for the reaction Cl 2( g ) leftharpoons 2 Cl ( g ) under the above conditions is x × 10-1. The value of x is (Rounded of to the nearest integer)

Question

At 1990 K and 1 atm pressure, there are equal number of Cl 2 molecules and Cl atoms in the reaction mixture. The value K P for the reaction Cl 2( g ) leftharpoons 2 Cl ( g ) under the above conditions is x × 10-1. The value of x is (Rounded of to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Cl 2 leftharpoons 2 Cl Let mol of both of Cl 2 and Cl is x P Cl =( x /2 x ) × 1=(1/2) P Cl 2=( x /2 x ) × 1=(1/2) K p =(((1/2))2/(1)2)=(1/2)=0.5 ⇒ 5 × 10-1

Q. At 1990K and 1 atm pressure, there are equal number of Cl2​ molecules and Cl atoms in the reaction mixture. The value KP​ for the reaction Cl2(g)​⇌2Cl(g)​ under the above conditions is x×10−1. The value of x is ________ (Rounded of to the nearest integer)

Cl2​⇌2Cl Let mol of both of Cl2​ and Cl is x PCl​=2xx​×1=21​ PCl2​​=2xx​×1=21​ Kp​=21​(21​)2​=21​=0.5 ⇒5×10−1

$C l_{2} ⇌ 2 Cl$

Let mol of both of $C l_{2}$ and $Cl$ is $x$

$P_{Cl} = \frac{x}{2 x} \times 1 = \frac{1}{2}$

$P_{C l_{2}} = \frac{x}{2 x} \times 1 = \frac{1}{2}$

$K_{p} = \frac{( \frac{1}{2} ) ^{2}}{\frac{1}{2}} = \frac{1}{2} = 0.5$

$\Rightarrow 5 \times 1 0^{- 1}$