At 10° C, the osmotic pressure of urea solution is 500 mm. The solution is diluted and the temperature is raised to 25° C, when the osmotic pressure is found to be 105.3 mm. Determine extent of dilution ( V 2 / V 1) ?

Question

At 10° C, the osmotic pressure of urea solution is 500 mm. The solution is diluted and the temperature is raised to 25° C, when the osmotic pressure is found to be 105.3 mm. Determine extent of dilution ( V 2 / V 1) ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P propto CT ( P 1/ C 1 T 1)=( P 2/ C 2 T 2) P 1=500 mm P 2=105.3 C 1= C 1 C 2= ? T 1=10+273=283 K (500/C1 × 283)=(105.3/C2 × 298) C1=1 / V1 (V1 × 500/283)=(V2 × 105.3/298) C2=1 / V2 V2=5 V1

Q. At 10∘C, the osmotic pressure of urea solution is 500mm. The solution is diluted and the temperature is raised to 25∘C, when the osmotic pressure is found to be 105.3mm. Determine extent of dilution (V2​/V1​) ?

P∝CT C1​T1​P1​​=C2​T2​P2​​ P1​=500mmP2​=105.3 C1​=C1​C2​= ? T1​=10+273=283K C1​×283500​=C2​×298105.3​C1​=1/V1​ 283V1​×500​=298V2​×105.3​C2​=1/V2​ V2​=5V1​

Q. At $1 0^{\circ} C$ , the osmotic pressure of urea solution is $500 mm$ . The solution is diluted and the temperature is raised to $2 5^{\circ} C$ , when the osmotic pressure is found to be $105.3 mm$ . Determine extent of dilution $(V_{2} / V_{1})$ ?