Assuming the mass of the earth as text6.64× 1024 kg and the average mass of the atoms that make up the earth as 40 u (atomic mass unit), the number of atoms in the earth is approximately

Question

Assuming the mass of the earth as text6.64× 1024 kg and the average mass of the atoms that make up the earth as 40 u (atomic mass unit), the number of atoms in the earth is approximately (A) 1030 (B) 1040 (C) 1050 (D) 1060

Tardigrade Admin · Accepted Answer

1a.m.u=1u= text1.6 × 10- 27 kg 40u=40× text1.6× 10- 27 kg Number of atoms in earth, =(6.64 × 1024/40 × 1.6 × 10- 27) = 1050

Q. Assuming the mass of the earth as $6.64 \times 1 0^{24} k g$ and the average mass of the atoms that make up the earth as $40 u$ (atomic mass unit), the number of atoms in the earth is approximately

$1 0^{30}$

$1 0^{40}$

$1 0^{50}$

$1 0^{60}$

$1 a . m . u = 1 u = 1.6 \times 1 0^{- 27} k g$
$40 u = 40 \times 1.6 \times 1 0^{- 27} k g$
Number of atoms in earth,
$= \frac{6.64 \times 1 0 ^{24}}{40 \times 1.6 \times 1 0 ^{- 27}}$ = $1 0^{50}$

Q. Assuming the mass of the earth as 6.64×1024kg and the average mass of the atoms that make up the earth as 40u (atomic mass unit), the number of atoms in the earth is approximately

1030

1040

1050

1060