Assuming the formation of an ideal solution, determine the boiling point (in degree celsius) of a mixture containing 1560 g benzene (molar mass =78 ) and 1125 g chlorobenzene (molar mass =112.5 ) using the following against an external pressure of 1000 torr.

Question

Assuming the formation of an ideal solution, determine the boiling point (in degree celsius) of a mixture containing 1560 g benzene (molar mass =78 ) and 1125 g chlorobenzene (molar mass =112.5 ) using the following against an external pressure of 1000 torr. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

20 moles C 6 H 6, 10 moles C 6 H 5 Cl ⇒ X B =(2/3), X C =(1/3) at t=100° C ⇒ p s =300 × (1/3)+1350 × (2/3) =100+900(=1000)

Q. Assuming the formation of an ideal solution, determine the boiling point (in degree celsius) of a mixture containing $1560 g$ benzene (molar mass $= 78$ ) and $1125 g$ chlorobenzene (molar mass $= 112.5$ ) using the following against an external pressure of $1000$ torr.

$20$ moles $C_{6} H_{6}, 10$ moles $C_{6} H_{5} Cl$
$\Rightarrow X_{B} = \frac{2}{3}, X_{C} = \frac{1}{3}$
at $t = 10 0^{\circ} C \Rightarrow p_{s} = 300 \times \frac{1}{3} + 1350 \times \frac{2}{3}$
$= 100 + 900 (= 1000)$

Q. Assuming the formation of an ideal solution, determine the boiling point (in degree celsius) of a mixture containing 1560g benzene (molar mass =78 ) and 1125g chlorobenzene (molar mass =112.5 ) using the following against an external pressure of 1000 torr.

20 moles C6​H6​,10 moles C6​H5​Cl ⇒XB​=32​,XC​=31​ at t=100∘C⇒ps​=300×31​+1350×32​ =100+900(=1000)

Q. Assuming the formation of an ideal solution, determine the boiling point (in degree celsius) of a mixture containing $1560 g$ benzene (molar mass $= 78$ ) and $1125 g$ chlorobenzene (molar mass $= 112.5$ ) using the following against an external pressure of $1000$ torr.

$20$ moles $C_{6} H_{6}, 10$ moles $C_{6} H_{5} Cl$
$\Rightarrow X_{B} = \frac{2}{3}, X_{C} = \frac{1}{3}$
at $t = 10 0^{\circ} C \Rightarrow p_{s} = 300 \times \frac{1}{3} + 1350 \times \frac{2}{3}$
$= 100 + 900 (= 1000)$