For the branch containing A,B and C. Req=23R
Current in A:I1=ReqE=3R2E
Current in each of B and C:I1′=2I1=3RE
For the branch containing D,E,F,G and H: Req=37R
Current through D and H:I2=7R3E
Current through each of E,F and G: I2′=3I2=7RE Since I1>I2>I1′>I2′ A>D=H>B=C>E=F=G