Assume the solubility of PbCl2 in water is S mol L- 1 and its solubility product is Ksp . The relation between Ksp and S is represented as S=√[3](Ksp/x) . The value of x is.

Question

Assume the solubility of PbCl2 in water is S mol L- 1 and its solubility product is Ksp . The relation between Ksp and S is represented as S=√[3](Ksp/x) . The value of x is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

underset(S)PbCl 2 leftharpoons underset(S)Pb 2++ underset(2S)2 Cl - Ks p=[P b2 +][C l]2 =S× (2 S)2=4S3 ∴ S=√[3](KS P/4) ∴ Value of x=4

Q. Assume the solubility of $P b C l_{2}$ in water is $S m o l L^{- 1}$ and its solubility product is $K_{s p}$ . The relation between $K_{s p}$ and $S$ is represented as $S = 3 \frac{K _{s p}}{x}$ . The value of $x$ is_____.

$(S) P b C l_{2} ⇌ (S) P b^{2 +} + (2 S) 2 C l^{-}$
$K_{s p} = [P b^{2 +}] [Cl]^{2}$
$= S \times (2 S)^{2} = 4 S^{3}$
$∴ S = 3 \frac{K _{SP}}{4}$
$∴$ Value of $x = 4$

Q. Assume the solubility of PbCl2​ in water is SmolL−1 and its solubility product is Ksp​ . The relation between Ksp​ and S is represented as S=3xKsp​​​ . The value of x is_____.

(S)PbCl2​​⇌(S)Pb2+​+(2S)2Cl−​ Ksp​=[Pb2+][Cl]2 =S×(2S)2=4S3 ∴S=34KSP​​​ ∴ Value of x=4

Q. Assume the solubility of $P b C l_{2}$ in water is $S m o l L^{- 1}$ and its solubility product is $K_{s p}$ . The relation between $K_{s p}$ and $S$ is represented as $S = 3 \frac{K _{s p}}{x}$ . The value of $x$ is_____.

$(S) P b C l_{2} ⇌ (S) P b^{2 +} + (2 S) 2 C l^{-}$
$K_{s p} = [P b^{2 +}] [Cl]^{2}$
$= S \times (2 S)^{2} = 4 S^{3}$
$∴ S = 3 \frac{K _{SP}}{4}$
$∴$ Value of $x = 4$