Question

Assume that during electrolysis of $AgN{O}_3$, only $H_{2}O$ is electrolysed and $O_2$ is formed as :-
$2H_{2}O\to 4H^{+}+O_2+4e^{-}$
$O_2$ formed at NTP due to passage of $2A$ of current for $965s$ is :-

• A. 0.112 L
• B. 0.224 L
• C. 11.2 L
• D. 22.4 L

Answer 1

Answer: (A)

$W_{O_2}=\frac{E_w}{96500}\times It$