Assume that a neutron breaks into a proton and an electron. The energy released during this process is: (Mass of neutron = 1.6725 × 10-27 kg, Mass of proton = 1.6725 × 10-27 kg, Mass of electron = 9 × 10-31 kg )

Question

Assume that a neutron breaks into a proton and an electron. The energy released during this process is: (Mass of neutron = 1.6725 × 10-27 kg, Mass of proton = 1.6725 × 10-27 kg, Mass of electron = 9 × 10-31 kg ) (A) 0.51 MeV (B) 7.10 MeV (C) 6.30 MeV (D) 5.4 MeV

Tardigrade Admin · Accepted Answer

0n1 arrow 1H1+-1e0+ barv+Q Δ m=mn-mα-me = (1.6725 × 10-27 - 1.6725 × 10-27 - 9 × 10-31) kg =-9×10-31×(3×108)2 Energy = 9× 10-31 × (3 × 108)2 = 0.511 MeV Which is nearly equal to 0.73 Mev but as energy will be required. since mass is increasing so answer = -0.511 Mev

Q. Assume that a neutron breaks into a proton and an electron. The energy released during this process is :
(Mass of neutron $= 1.6725 \times 1 0^{- 27} k g$ ,
Mass of proton $= 1.6725 \times 1 0^{- 27} k g$ ,
Mass of electron $= 9 \times 1 0^{- 31} k g$ )

$0.51 M e V$

$7.10 M e V$

$6.30 M e V$

$5.4 M e V$

Q. Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (Mass of neutron =1.6725×10−27kg, Mass of proton =1.6725×10−27kg, Mass of electron =9×10−31kg )

0.51MeV

7.10MeV

6.30MeV

5.4MeV

0​n1→1​H1+−1​e0+vˉ+Q Δm=mn​−mα​−me​ =(1.6725×10−27−1.6725×10−27−9×10−31)kg =−9×10−31×(3×108)2 Energy =9×10−31×(3×108)2 =0.511MeV Which is nearly equal to 0.73Mev but as energy will be required. since mass is increasing so answer =−0.511Mev

Q. Assume that a neutron breaks into a proton and an electron. The energy released during this process is :
(Mass of neutron $= 1.6725 \times 1 0^{- 27} k g$ ,
Mass of proton $= 1.6725 \times 1 0^{- 27} k g$ ,
Mass of electron $= 9 \times 1 0^{- 31} k g$ )

$0.51 M e V$

$7.10 M e V$

$6.30 M e V$

$5.4 M e V$