Assertion While applying Ampere's circuital law to given surfaces with same perimeter, the left hand side oint B ⋅ d l=μ0 i(t) has not changed but the right hand side is zero. Reason No current passes through the surface.

Question

Assertion While applying Ampere's circuital law to given surfaces with same perimeter, the left hand side oint B ⋅ d l=μ0 i(t) has not changed but the right hand side is zero. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6b72f343a7e4dc07429309025a0c604f-.png" /> Reason No current passes through the surface. (A) Both Assertion and Reason are correct and Reason is the correct explanation of Assertion. (B) Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion. (C) Assertion is correct but Reason is incorrect. (D) Assertion is incorrect but Reason is correct.

Tardigrade Admin · Accepted Answer

On applying Ampere's circuital law to such surfaces with the same perimeter, we find that the left hand side of equation

\oint B . d l = μ_{0} i (t)

has not changed but the right hand side is zero and not

μ_{0} i

.
Since, no current passes through the surface.

Q. Assertion While applying Ampere's circuital law to given surfaces with same perimeter, the left hand side ∮B⋅dl=μ0​i(t) has not changed but the right hand side is zero. Reason No current passes through the surface.

Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.

Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.

Assertion is correct but Reason is incorrect.

Assertion is incorrect but Reason is correct.

On applying Ampere's circuital law to such surfaces with the same perimeter, we find that the left hand side of equation ∮B.dl=μ0​i(t) has not changed but the right hand side is zero and not μ0​i. Since, no current passes through the surface.

Q. Assertion While applying Ampere's circuital law to given surfaces with same perimeter, the left hand side $\oint B \cdot d l = μ_{0} i (t)$ has not changed but the right hand side is zero.

Reason No current passes through the surface.

On applying Ampere's circuital law to such surfaces with the same perimeter, we find that the left hand side of equation $\oint B . d l = μ_{0} i (t)$ has not changed but the right hand side is zero and not $μ_{0} i$ .
Since, no current passes through the surface.