The oxidation states of the given compounds are
VO2+ : x + 2(-2) = +1 ⇒ x = +5
Cr2O72− : 2x + 7(-2) = -2 ⇒ 2x = +12 ⇒ x = +6
MnO4− : x + 4(-2) = -1 x = -1 + 8 = + 7
The correct order of oxidising power is
VO2+ < Cr2O72− < MnO4−
due to the increasing stability of the lower species to which they are reduced.