Q.
Assertion : Oxidation state of oxygen in OF2 and Na2O is +2 and −2 respectively. Reason: Oxygen is an electronegative element.
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Classification of Elements and Periodicity in Properties
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Solution:
The electronegativity order of three elements involved in these compounds is F>O>Na. Hence in OF2 molecule, F is more electronegative than O, element F is given oxidation state −1 and thus, O shows +2 oxidation state. On the other hand, in Na2O,O is more electronegative than Na, hence, Na is given +1 oxidation state and O shows oxidation state −2.