Assertion: It one gram of ice is mixed with 1 g of water at , then the final temperature of mixture is zero. Reason: Latent heat of ice is 80 cal/g.

Question

Assertion: It one gram of ice is mixed with 1 g of water at , then the final temperature of mixture is zero. Reason: Latent heat of ice is 80 cal/g. (A) If both Assertion and Reason are true and Reason is the correct explanation of Assertion. (B) If both Assertion and Reason are true but Reason is not the correct explanation of Assertion. (C) If Assertion is true but Reason is false. (D) If both Assertion and Reason are false.

Tardigrade Admin · Accepted Answer

Heat required by ice to melt =1× 80=80 text cal Heat lost by water is cooling from text80 texto textC to text0 texto textC text. =1× 1× (80=0) =80 textcal From principle of colorimetry heat lost = Heat gained. Thus, the final temperature of the mixture will be text0 texto textC text.

Q. Assertion: It one gram of ice is mixed with 1 g of water at
, then the final temperature of mixture is zero. Reason: Latent heat of ice is 80 cal/g.

If both Assertion and Reason are true and Reason is the correct explanation of Assertion.

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

If Assertion is true but Reason is false.

If both Assertion and Reason are false.

Heat required by ice to melt $= 1 \times 80 = 80 cal$ Heat lost by water is cooling from $80^{o} C$ to $0^{o} C .$ $= 1 \times 1 \times (80 = 0)$ $= 80 cal$ From principle of colorimetry heat lost = Heat gained. Thus, the final temperature of the mixture will be $0^{o} C .$

Q. Assertion: It one gram of ice is mixed with 1 g of water at , then the final temperature of mixture is zero. Reason: Latent heat of ice is 80 cal/g.