Assertion: If an electron and proton enter a perpendicular magnetic field with equal momentum, then radius of curve for electron is more than that of proton. Reason: Electron has less mass than proton.

Question

Assertion: If an electron and proton enter a perpendicular magnetic field with equal momentum, then radius of curve for electron is more than that of proton. Reason: Electron has less mass than proton. (A) If both the assertion and reason are true and reason explains the assertion. (B) If both the assertion and reason are true but reason does not explain the assertion. (C) If assertion is true but reason is false. (D) If assertion is false but reason is true.

Tardigrade Admin · Accepted Answer

When a charged particle enters in perpendicular magnetic field than radius of curved path is given by

r = \frac{m v}{qB} = \frac{p}{qB}

As momentum

p

is constant

∴ r \propto \frac{1}{q}

As

e^{-}

and proton have same charge

\frac{r _{e}^{-}}{r _{p}^{+}} = \frac{q _{e}^{-}}{q _{e}^{+}} = 1

Assertion is false, but reason is true

Q. Assertion : If an electron and proton enter a perpendicular magnetic field with equal momentum, then radius of curve for electron is more than that of proton. Reason : Electron has less mass than proton.

If both the assertion and reason are true and reason explains the assertion.

If both the assertion and reason are true but reason does not explain the assertion.

If assertion is true but reason is false.

If assertion is false but reason is true.

When a charged particle enters in perpendicular magnetic field than radius of curved path is given by r=qBmv​=qBp​ As momentum p is constant ∴r∝q1​ As e− and proton have same charge rp+​re−​​=qe+​qe−​​=1 Assertion is false, but reason is true

Q. Assertion : If an electron and proton enter a perpendicular magnetic field with equal momentum, then radius of curve for electron is more than that of proton.
Reason : Electron has less mass than proton.