Assertion: If 3 x+8 2, then x ∈ -1,0,1,2, ldots when x is an integer. Reason: The solution set of the inequality 4 x+3

Question

Assertion: If 3 x+8 > 2, then x ∈ -1,0,1,2, ldots when x is an integer. Reason: The solution set of the inequality 4 x+3 < 5 x+7 ∀ x ∈ R is [4, ∞) (A) Assertion is correct, reason is correct; reason is a correct explanation for assertion. (B) Assertion is correct, reason is correct; reason is not a correct explanation for assertion (C) Assertion is correct, reason is incorrect (D) Assertion is incorrect, reason is correct.

Tardigrade Admin · Accepted Answer

Assertion is correct. 3 x+8 >2 ⇒ 3 x>-6 ⇒ x>-2 ⇒ x ∈ -1,0,1,2, ldots Reason is incorrect. 4 x+3<5 x+7 -x<4 ⇒ x>-4 ⇒ x ∈(-4, ∞)

Q. Assertion $:$ If $3 x + 8 > 2$ , then $x \in {- 1, 0, 1, 2, \dots}$ , when $x$ is an integer. Reason : The solution set of the inequality $4 x + 3 < 5 x + 7$ $\forall x \in R$ is $[4, \infty)$

Assertion is correct, reason is correct; reason is a correct explanation for assertion.

Assertion is correct, reason is correct; reason is not a correct explanation for assertion

Assertion is correct, reason is incorrect

Assertion is incorrect, reason is correct.

Assertion is correct. $3 x + 8 > 2$
$\Rightarrow 3 x > - 6$
$\Rightarrow x > - 2$
$\Rightarrow x \in {- 1, 0, 1, 2, \dots}$
Reason is incorrect. $4 x + 3 < 5 x + 7$
$- x < 4 \Rightarrow x > - 4$
$\Rightarrow x \in (- 4, \infty)$

Q. Assertion : If 3x+8>2, then x∈{−1,0,1,2,…}, when x is an integer. Reason : The solution set of the inequality 4x+3<5x+7 ∀x∈R is [4,∞)