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Q. Assertion $:$ If $3 x+8 > 2$, then $x \in\{-1,0,1,2, \ldots\}$, when $x$ is an integer. Reason : The solution set of the inequality $4 x+3 < 5 x+7$ $\forall x \in R$ is $[4, \infty)$

Linear Inequalities

Solution:

Assertion is correct. $3 x+8 >2$
$ \Rightarrow 3 x>-6 $
$\Rightarrow x>-2$
$\Rightarrow x \in\{-1,0,1,2, \ldots\}$
Reason is incorrect. $4 x+3<5 x+7$
$-x<4 \Rightarrow x>-4$
$ \Rightarrow x \in(-4, \infty)$