Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Assertion: HC ≡ C -is more stable than H 2 C = CH -. Reason: HC ≡ C -has more s-character than H 2 C = CH -.
Q.
Assertion :
H
C
≡
C
−
is more stable than
H
2
C
=
C
H
−
.
Reason :
H
C
≡
C
−
has more s-character than
H
2
C
=
C
H
−
.
3347
197
AIIMS
AIIMS 2012
Hydrocarbons
Report Error
A
If both assertion and reason are true and reason is the correct explanation of assertion
51%
B
If both assertion and reason are true but reason is not the correct explanation of assertion
24%
C
If assertion is true but reason is false
13%
D
If both assertion and reason are false
11%
Solution:
H
C
≡
C
−
has
50%
s-character and
H
2
C
=
C
H
−
has
33%
s-character. Stability of carbanions increases with an increase in the s-character at the carbanion. So
H
C
≡
C
−
is more stable than
H
2
C
=
C
H
−
.