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Tardigrade
Question
Mathematics
Assertion: For any two sets A and B , A - B ⊂ B ' Reason: If A be any set, then A ∩ A'= φ
Q.
Assertion :
For any two sets
A
and
B
,
A
−
B
⊂
B
′
Reason :
If A be any set, then
A
∩
A
′
=
ϕ
3985
216
Sets
Report Error
A
Assertion is correct, reason is correct; reason is a correct explanation for assertion.
100%
B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
0%
C
Assertion is correct, reason is incorrect
0%
D
Assertion is incorrect, reason is correct.
0%
Solution:
Let
x
∈
A
−
B
⇒
x
∈
A
and
x
∈
/
B
⇒
x
∈
A
and
x
∈
B
′
⇒
x
∈
B
′
∴
A
−
B
⊂
B
′
It is true
A
∩
A
′
=
ϕ
[by complement laws]
Hence, both Assertion and Reason are correct but Reason is not a correct explanation of Assertion.