Assertion (A) % of phosphorus in an organic compound can be estimated by formula (31 × m1 × 100/1877 × m) Reason (R) Molar mass of ( NH 4)3 PO 4 ⋅ 12 MoO 3=1877 g

Question

Assertion (A) % of phosphorus in an organic compound can be estimated by formula (31 × m1 × 100/1877 × m) Reason (R) Molar mass of ( NH 4)3 PO 4 ⋅ 12 MoO 3=1877 g (A) Both A and R are correct; R is the correct explanation of A. (B) Both A and R are correct; R is not the correct explanation of A. (C) A is correct; R is incorrect. (D) R is correct; A is incorrect.

Tardigrade Admin · Accepted Answer

Since, molar mass of ( NH 4)3 PO 4 ⋅ 12 MoO 3 is 1877 g, the % of P can be calculated as % of P =(31 × m1 × 100/1877 × m) % Thus, both A and R are correct and R is the correct explanation of A.

Q. Assertion (A) $%$ of phosphorus in an organic compound can be estimated by formula $\frac{31 \times m _{1} \times 100}{1877 \times m}$
Reason (R) Molar mass of $(N H_{4})_{3} P O_{4} \cdot 12 M o O_{3} = 1877 g$

Both $A$ and $R$ are correct; $R$ is the correct explanation of $A$ .

Both $A$ and $R$ are correct; $R$ is not the correct explanation of $A$ .

$A$ is correct; $R$ is incorrect.

$R$ is correct; $A$ is incorrect.

Since, molar mass of $(N H_{4})_{3} P O_{4} \cdot 12 M o O_{3}$ is $1877 g$ , the $%$ of $P$ can be calculated as
$%$ of $P = \frac{31 \times m _{1} \times 100}{1877 \times m} %$
Thus, both $A$ and $R$ are correct and $R$ is the correct explanation of $A$ .

Q. Assertion (A) % of phosphorus in an organic compound can be estimated by formula 1877×m31×m1​×100​ Reason (R) Molar mass of (NH4​)3​PO4​⋅12MoO3​=1877g

Both A and R are correct; R is the correct explanation of A.

Both A and R are correct; R is not the correct explanation of A.

A is correct; R is incorrect.

R is correct; A is incorrect.