Question

Assertion (A) $\%$ of phosphorus in an organic compound can be estimated by formula $\frac{31 \times m_{1} \times 100}{1877 \times m}$
Reason (R) Molar mass of $\left( NH _{4}\right)_{3} PO _{4} \cdot 12 MoO _{3}=1877 \,g$

• A. Both $A$ and $R$ are correct; $R$ is the correct explanation of $A$.
• B. Both $A$ and $R$ are correct; $R$ is not the correct explanation of $A$.
• C. $A$ is correct; $R$ is incorrect.
• D. $R$ is correct; $A$ is incorrect.

Answer 1

Answer: (A)

Since, molar mass of $\left( NH _{4}\right)_{3} PO _{4} \cdot 12 MoO _{3}$ is $1877\, g$, the $\%$ of $P$ can be calculated as
$\%$ of $ P =\frac{31 \times m_{1} \times 100}{1877 \times m} \%$
Thus, both $A$ and $R$ are correct and $R$ is the correct explanation of $A$.