Aspirin is a pain reliever with pKa=2 . Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

Question

Aspirin is a pain reliever with pKa=2 . Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be (A) 0.5 (B) 1.0 (C) 0.8 (D) 2.0

Tardigrade Admin · Accepted Answer

Aspirin is a weak acid =0.09× 2 text g/100 text mL =1.8g L-1 (1.8/180)mol L-1=0.01 M pH (weak acid) =(1/2)[pKa- log C]=(1/2)(2+2)=2

Q.
Aspirin is a pain reliever with $p K_{a} = 2$ . Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

0.5

1.0

0.8

2.0

Aspirin is a weak acid $= 0.09 \times 2 g /100 m L$
$= 1.8 g L^{- 1}$ $\frac{1.8}{180} m o l L^{- 1} = 0.01 M$ pH (weak acid)
$= \frac{1}{2} [p K_{a} - lo g C] = \frac{1}{2} (2 + 2) = 2$

Q. Aspirin is a pain reliever with pKa​=2 . Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

0.5

1.0

0.8

2.0

Aspirin is a weak acid =0.09×2g/100mL =1.8gL−1 1801.8​molL−1=0.01M pH (weak acid) =21​[pKa​−logC]=21​(2+2)=2

Q.
Aspirin is a pain reliever with $p K_{a} = 2$ . Two tablets each containing 0.09 g of aspirin are dissolved in 100 mL solution. pH will be

Aspirin is a weak acid $= 0.09 \times 2 g /100 m L$
$= 1.8 g L^{- 1}$ $\frac{1.8}{180} m o l L^{- 1} = 0.01 M$ pH (weak acid)
$= \frac{1}{2} [p K_{a} - lo g C] = \frac{1}{2} (2 + 2) = 2$