Question

As the $s$-character of hybridised orbital increases, the bond angle

• A. increases
• B. decrease
• C. becomes zero
• D. does not change

Answer 1

Answer: (A)

$s$-character increases with increase in bond angle.

Hybridisation	$\%$ of $s$ character	Bond angle
$sp$	$50$	$18^{\circ }$
$s{p}^2$	$33.3$	$120^{\circ }$
$s{p}^3$	$25$	$109.28^{\circ }$