Q. As the $s$-character of hybridised orbital increases, the bond angle
AMUAMU 2007
Solution:
$s$-character increases with increase in bond angle.
Hybridisation
$\%$ of $s$ character
Bond angle
$sp$
$50$
$18^{\circ}$
$sp^2$
$33.3$
$120^{\circ}$
$sp^3$
$25$
$109.28^{\circ}$
| Hybridisation | $\%$ of $s$ character | Bond angle |
|---|---|---|
| $sp$ | $50$ | $18^{\circ}$ |
| $sp^2$ | $33.3$ | $120^{\circ}$ |
| $sp^3$ | $25$ | $109.28^{\circ}$ |