As shown in the figure, two blocks of masses 4 kg and 5 kg are at rest on the ground. The masses are connected by a massless string passing over a smooth and light pulley. A 200 N force is applied on the pulley. Find the difference in accelerations (in m / s 2 ) of the blocks.

Question

As shown in the figure, two blocks of masses 4 kg and 5 kg are at rest on the ground. The masses are connected by a massless string passing over a smooth and light pulley. A 200 N force is applied on the pulley. Find the difference in accelerations (in m / s 2 ) of the blocks. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

aA=(100-40/4)=15 m / s 2, aB=(100-50/5)=10 m / s 2 ⇒ aA-aB=15-10=5 m / s 2

Q. As shown in the figure, two blocks of masses $4 k g$ and $5 k g$ are at rest on the ground. The masses are connected by a massless string passing over a smooth and light pulley. A $200 N$ force is applied on the pulley. Find the difference in accelerations (in $m / s^{2}$ ) of the blocks.

$a_{A} = \frac{100 - 40}{4} = 15 m / s^{2},$
$a_{B} = \frac{100 - 50}{5} = 10 m / s^{2}$
$\Rightarrow a_{A} - a_{B} = 15 - 10 = 5 m / s^{2}$

Q. As shown in the figure, two blocks of masses 4kg and 5kg are at rest on the ground. The masses are connected by a massless string passing over a smooth and light pulley. A 200N force is applied on the pulley. Find the difference in accelerations (in m/s2 ) of the blocks.

aA​=4100−40​=15m/s2, aB​=5100−50​=10m/s2 ⇒aA​−aB​=15−10=5m/s2

Q. As shown in the figure, two blocks of masses $4 k g$ and $5 k g$ are at rest on the ground. The masses are connected by a massless string passing over a smooth and light pulley. A $200 N$ force is applied on the pulley. Find the difference in accelerations (in $m / s^{2}$ ) of the blocks.

$a_{A} = \frac{100 - 40}{4} = 15 m / s^{2},$
$a_{B} = \frac{100 - 50}{5} = 10 m / s^{2}$
$\Rightarrow a_{A} - a_{B} = 15 - 10 = 5 m / s^{2}$