As shown in the figure, a long straight conductor with semicircular are of radius (π/10) m is carrying current I =3 A. The magnitude of the magnetic field. at the center O of the arc is: (The permeability of the vacuum =4 π × 10-7 NA -2 )

Question

As shown in the figure, a long straight conductor with semicircular are of radius (π/10) m is carrying current I =3 A. The magnitude of the magnetic field. at the center O of the arc is: (The permeability of the vacuum =4 π × 10-7 NA -2 ) (A) 6 μ T (B) 4 μ T (C) 3 μ T (D) 1 μ T

Tardigrade Admin · Accepted Answer

B C =(μ0 I /4 π R )(π)( B text at centre of circular arc ) =(μ0 I /4 R )=(4 π × 10-7 × 3/4 × (π)10) =3 × 10-6 T =3 μ T

Q. As shown in the figure, a long straight conductor with semicircular are of radius $\frac{π}{10} m$ is carrying current $I = 3 A$ . The magnitude of the magnetic field. at the center $O$ of the arc is :
(The permeability of the vacuum $= 4 π \times 1 0^{- 7} N A^{- 2}$ )

$6 μ T$

$4 μ T$

$3 μ T$

$1 μ T$

$B_{C} = \frac{μ _{0} I}{4 π R} (π) (B at centre of circular arc)$
$= \frac{μ _{0} I}{4 R} = \frac{4 π \times 1 0 ^{- 7} \times 3}{4 \times \frac{π}{10}}$
$= 3 \times 1 0^{- 6} T = 3 μ T$

Q. As shown in the figure, a long straight conductor with semicircular are of radius 10π​m is carrying current I=3A. The magnitude of the magnetic field. at the center O of the arc is : (The permeability of the vacuum =4π×10−7NA−2 )

6μT

4μT

3μT

1μT